Find the X-intercepts of 3X^2+2Y^2+4XY-12=0

[From: ] [author: ] [Date: 12-08-16] [Hit: ]

What are the X-intercepts of that equation?

3(X^2)+2(Y^2)+4XY-12=0

When y = 0
3x^2 = 12
x = 2 and -2

Doing y = 0

3*x^2 - 12 = 0

x^2 = 4

x1 = 2, point (2; 0)
x2 = - 2, point ( - 2; 0)

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