I don't remember how to do this.. Please explain how you got the answer if you can.
A data set consists of the following data points:
(3,5), (5,8), (6,13)
The slope of the best fit line is 2.5. Find the y-intercept of this line.
A data set consists of the following data points:
(3,5), (5,8), (6,13)
The slope of the best fit line is 2.5. Find the y-intercept of this line.
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Let us assume that the data points can be connected by a straight line. The equation describing such a line can be written as:
y = ax + b,
where, a and b are constants.
The slope for the line is given as 2.5, therefore a = 2.5. Therefore,
y = 2.5x + b
If we try substituting the points (3,5), (5,8) and (6,13) in the equation one by one, we get:
5 = 7.5 + b, or b = -2.5
8 = 12.5 + b, or b = -4.5
13 = 15 + b, or b = -2
Since we have assumed a straight line and have received 3 different values for b, we need to take an average of these values, which gives b = -3. Therefore, our equation becomes:
y = 2.5x - 3
The y-intercept for the line can be found by putting x = 0 in this equation, which gives y = -3. In other words, the y-intercept of the line is (0, -3).
y = ax + b,
where, a and b are constants.
The slope for the line is given as 2.5, therefore a = 2.5. Therefore,
y = 2.5x + b
If we try substituting the points (3,5), (5,8) and (6,13) in the equation one by one, we get:
5 = 7.5 + b, or b = -2.5
8 = 12.5 + b, or b = -4.5
13 = 15 + b, or b = -2
Since we have assumed a straight line and have received 3 different values for b, we need to take an average of these values, which gives b = -3. Therefore, our equation becomes:
y = 2.5x - 3
The y-intercept for the line can be found by putting x = 0 in this equation, which gives y = -3. In other words, the y-intercept of the line is (0, -3).