force of magnetic 3.5 x 10^-16 N.
a. What is the magnitude of the magnetic field?
b. What is the direction of the magnetic force?
c. What will be the radius of the circular path in the magnetic field?
d. If, using the same magnetic field, a velocity selector was used to give the proton the speed of 5.0 x 10^6 m/s, what was the value of the electric field?
I am merely checking my work on the first two. I'm not sure about the last two. Any help would be appreciated greatly. Thank you!
a. What is the magnitude of the magnetic field?
b. What is the direction of the magnetic force?
c. What will be the radius of the circular path in the magnetic field?
d. If, using the same magnetic field, a velocity selector was used to give the proton the speed of 5.0 x 10^6 m/s, what was the value of the electric field?
I am merely checking my work on the first two. I'm not sure about the last two. Any help would be appreciated greatly. Thank you!
-
a) F = Bqv .. B = F/qv .. .. ►4.38^-4 T
b) As a +ve charge, it's movement represents a conventional current ..
Apply Fleming's left-hand rule .. .. ►Force is in the plane of the paper, towards the top.
c) Mag force F provides (=) the centripetal force ..
F = mv²/r
r = mv² / F .. .. (1.67^-27kg)(5.0^6m/s)² / 3.50^-16N .. .. .. ►r = 119.30 m
d) Selected velocity v = E/B
E = Bv .. .. 4.38^-4T x 5.0^6m/s .. .. .. ►E = 2190 V/m (=N/C)
b) As a +ve charge, it's movement represents a conventional current ..
Apply Fleming's left-hand rule .. .. ►Force is in the plane of the paper, towards the top.
c) Mag force F provides (=) the centripetal force ..
F = mv²/r
r = mv² / F .. .. (1.67^-27kg)(5.0^6m/s)² / 3.50^-16N .. .. .. ►r = 119.30 m
d) Selected velocity v = E/B
E = Bv .. .. 4.38^-4T x 5.0^6m/s .. .. .. ►E = 2190 V/m (=N/C)