How many 7 member squads can be made from 12 members if the same member is captain of both squads?
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Consider the 11 non-captain members. There are 11 choose 6 ways of forming 6 member squads all composed of no captain. In your column of squads where each row is a list of 6 member non-captain soldiers, add your captain to the list. Answer: 11 choose 6 or 462.
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Two 7 member squads would need 14 people and thus we have 2 common members in the squads. That would make 2 captains? If this is what you mean the answer would be:
C(12,2) x [ C(10,5) / 2 ] = [ 12! / ( 2! x 10! ) ] x [ 10! / ( 5! x 5! x 2 ) ] = 8316
The C mark means "combination" and you surely know the ! is factorial.
I hope that this helps!
C(12,2) x [ C(10,5) / 2 ] = [ 12! / ( 2! x 10! ) ] x [ 10! / ( 5! x 5! x 2 ) ] = 8316
The C mark means "combination" and you surely know the ! is factorial.
I hope that this helps!
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Only one 7 member squad can be made out of 12 members per one captain. There would have to be 2 squads of of to each with their own captain. If that makes any sense.
Edit: or there could be only one group of 7 members and one group of 5 members per one captain.
Maybe there's not enough information and i'm pushing myself to hard. I just want to be good at math lol.
Edit: or there could be only one group of 7 members and one group of 5 members per one captain.
Maybe there's not enough information and i'm pushing myself to hard. I just want to be good at math lol.
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462