Equation of a line passing through a point and is perpendicular to the horizontal line passing through point
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Equation of a line passing through a point and is perpendicular to the horizontal line passing through point

[From: ] [author: ] [Date: 11-12-16] [Hit: ]
and is in the form x = a.x = 1 is the equation.......
I do not know how to solve this question correctly.
Question: Find the equation of the line passing through (1,-3) and perpendicular to the horizontal line passing through (-1,-1).
My way of solving it: since (m1)(m2)=-1 for perpendicular lines, both slopes are 0 because a horizontal line has no slope.
So the thing is, then I just would have my answer as y=-3.
Solution in the textbook: x=1

Can someone please explain how to get to that answer and why it's an x= and not y= when talking about horizontal, please. I need to know to prepare for an exam tomorrow.

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An equation for a horizontal line through (1, -3) is y = -3.
A line perpendicular to a horizontal line is vertical, and is in the form x = a.

x = 1 is the equation.

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eh
1
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