I do not know how to solve this question correctly.
Question: Find the equation of the line passing through (1,-3) and perpendicular to the horizontal line passing through (-1,-1).
My way of solving it: since (m1)(m2)=-1 for perpendicular lines, both slopes are 0 because a horizontal line has no slope.
So the thing is, then I just would have my answer as y=-3.
Solution in the textbook: x=1
Can someone please explain how to get to that answer and why it's an x= and not y= when talking about horizontal, please. I need to know to prepare for an exam tomorrow.
Question: Find the equation of the line passing through (1,-3) and perpendicular to the horizontal line passing through (-1,-1).
My way of solving it: since (m1)(m2)=-1 for perpendicular lines, both slopes are 0 because a horizontal line has no slope.
So the thing is, then I just would have my answer as y=-3.
Solution in the textbook: x=1
Can someone please explain how to get to that answer and why it's an x= and not y= when talking about horizontal, please. I need to know to prepare for an exam tomorrow.
-
An equation for a horizontal line through (1, -3) is y = -3.
A line perpendicular to a horizontal line is vertical, and is in the form x = a.
x = 1 is the equation.
A line perpendicular to a horizontal line is vertical, and is in the form x = a.
x = 1 is the equation.
-
eh