Can you Help me Solve –3x2 – 4x – 4 = 0 please
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Can you Help me Solve –3x2 – 4x – 4 = 0 please

[From: ] [author: ] [Date: 11-12-16] [Hit: ]
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Please help <3 Best answer!

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–3x2 – 4x – 4 = 0

3x² + 4x + 4 = 0

I am going to solve this by completing the square. Before I do Read/Study this example
You were taught to take 1/2 of "b", then square that result and add it to both sides.
In this problwm you have to divide by "a" first. Notice this creates a fraction with the -3.
Here is a method not taught anymore. NO FRACTIONS till the last step.
2x² - 4x - 3 = 0
ax^2+bx+c=0
In this problem a=2 and b=-3
Here is what you do:
Multiply every term by 4a..........4a=....4(2)=..............8
Add b^2....................................b…
8(2x² - 4x - 3 = 0)
16x^2-32x-24=0
16x^2-32x=+24
16x^2-32x+9=+24+9.....You just created a Perfect Square Trinomial which is the pupose
......................................… Completing The Square................Now factor the left side
(4x-3)^2=33
sqrt[(4x-3)^2]="+-"sqrt(33)
4x-3="+-"sqrt(33)
4x=+3"+-"sqrt(33).................Now divide by 4.........creating your first fraction
.......+3"+-"sqrt(33)
X=******************..................… you are finished
...............4
If you did not follow, find the smartest math nerd you know and show this to them
or to your teacher. This method was last taught in the early 1900's.
Over 99% of math teachers and students DO NOT KNOW or have ever heard of this.
PASS IT ON

3x² + 4x + .... = - 4 + .....

Mult by 4a = 4(3) = 12

Add b² = (4)² = 16

36x² + 48x + ... = - 48

36x² + 48x + 16 = - 48 + 16

(6x + 4)² = - 32

√(6x + 4)² = +- √-32...................√-32 = √-16*√2 = 4i√2

6x + 4 = +- 4i√2.............Divide ALL by 2

3x + 2 = +- 2i√2

3x = - 2 +- 2i√2

........- 2 +- 2i√2
x = ----------------.......ANSWERS
...............3

If you have questions on this or any other math problem feel free
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