You walk 250 newtons N then 575 newtons W find the magnitude and direction of the resultant vector

show the step on how to get this
it wants t know the angle how do u get that

you probably mean that there are vectors with respective forces:
250 N Nthen 575 N W
this gives you (pythagoras) sqrt(250^2+575^2)=627 Newton direction NW or Arcos250/627 =66.5° from N

How to?
Draw a cross on a paper. Vertical up = North.
Then East is to the right and West to the left.
Draw a line 2.5 inch North, from the center. then 5.75 inch long to the left.
Then draw a line from there to the center.
The Magnitude (length) is then 6.7 inch
(we now used a scale of 1 inch = 100 N)
Direction is 66.5° from the north, or 156.5° from the east. (or direction for x-axis)

Newtons aren't a measure of distance, they're a measure of force.

In this case, there are two forces; one toward the N of 250N and one toward the W of 575N. You're supposed to find out which direction and force they combine to provide, called the net force.

The net force is the same as if there was only force. In this case, the resultant force is 627N in the direction of 293.5 degrees.

Walking cannot be represented in newtons, perhaps it was in m?

Anyway, use Pythagorean theorem:

resultant vector ² = (250 m)² + (575 m)²
resultant vector ² = 62,500 m² + 330,625 m²
resultant vector ² = 393,125 m²
resultant vector = √393,125 m²
resultant vector ≈ 627 m
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when did newtons become a measure of distance?