How do you find y, (2/3)y+y=1
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How do you find y, (2/3)y+y=1

[From: ] [author: ] [Date: 11-12-05] [Hit: ]
1 divided by 5/3 is equal to 1 multiplied by 3/5 which equals 3/5.So since weve isolated the y, and crossed out the 5/3 on that side.y= 1 times 3/5.......
I know the answer is y=3/5, but I still do not understand how y was found

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Multiply everything by 3 so you get
2y+3y=3 =>
5y=3 =>
so y=3/5

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Add 2/3y and y together because they are like terms.
That equals, 5/3y.
So 5/3y = 1.
Then, we isolate the y by dividing both sides by 5/3.
1 divided by 5/3 is equal to 1 multiplied by 3/5 which equals 3/5.
So since we've isolated the y, and crossed out the 5/3 on that side.
y= 1 times 3/5.
y = 3/5

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2/3y + 3/3y = 1

5/3y = 1

3/5(5/3)y = 1(3/5)

y = 3/5
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