If (2,1) is a critical point of f and fxx(2,1)fyy(2,1) < [fxy(2,1)]^2, then f has a saddle point at (2,1).
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HOME > > If (2,1) is a critical point of f and fxx(2,1)fyy(2,1) < [fxy(2,1)]^2, then f has a saddle point at (2,1).

If (2,1) is a critical point of f and fxx(2,1)fyy(2,1) < [fxy(2,1)]^2, then f has a saddle point at (2,1).

[From: ] [author: ] [Date: 11-12-05] [Hit: ]
1) = fxx(2,1)fyy(2,1) - [fxy(2,I hope this helps!......
determine whether the statement is true or false. If it is true,
explain why. If it is false, explain why or give an example that disproves the
statement.

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True, since D(2, 1) = fxx(2,1)fyy(2,1) - [fxy(2,1)]^2 < 0.

I hope this helps!
1
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