Find the antiderivative of x^2(1+x^3)^5
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Find the antiderivative of x^2(1+x^3)^5

[From: ] [author: ] [Date: 11-11-16] [Hit: ]
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I have tried this multiple times and i get close to the answer that is needed. But I never properly answer it. The answer is suppose to be (1/18)(1+x^3)^6+c. But i always get (1/18)x(1+x^3)^6, please help

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I = ∫ x² (1 + x³)^5 dx
Let u = 1 + x³
du = 3x² dx
du/3 = x² dx

I = (1/3) ∫ u^5 du
I = (1/18) u^6 + C
I = (1/18) (1 + x²)^6 + C

C is the constant of integration.

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Pleased to help----thank you.

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