Given the following function, y = log(3 – x)determine the range of the asymptotes of the function. Indeterminate Form
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I haven't heard of "range of the asymptotes", nor am I familiar with what "indeterminate form" means in this context.
However, since the function log x has x=0 as its asymptote,
the asymptote for y = log(3 - x) is
3 - x = 0
i.e. the vertical line x = 3.
log x is defined for positive x, hence
y = log(3 - x) is defined for 3 - x > 0
i.e. x < 3
In the domain(-∞, 3) the function takes all real values,
i.e. its range is (-∞, ∞)
However, since the function log x has x=0 as its asymptote,
the asymptote for y = log(3 - x) is
3 - x = 0
i.e. the vertical line x = 3.
log x is defined for positive x, hence
y = log(3 - x) is defined for 3 - x > 0
i.e. x < 3
In the domain(-∞, 3) the function takes all real values,
i.e. its range is (-∞, ∞)