CO ORDINATE GEOMETRY HELP NEEDED BADLY!
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CO ORDINATE GEOMETRY HELP NEEDED BADLY!

[From: ] [author: ] [Date: 11-11-16] [Hit: ]
Need to revise your post.a).b).c).......
The points a and b have coords (4.6) and (12,2) the straight line l1 passes through a and b.

a) find an equation for l1 in the form ax+by+c=0/

b) write down an equation for l2.

c) the lines l1 and l2 intersect at point c
find the coordinates of C.


could anyone help with this please?

-
No given information for l2. Need to revise your post.
*********************
a).
slope m of L1:
m = (2 - 6)/(12 - 4) = -1/2

equation L1
y - 6 = (-1/2)(x - 4)
y - 6 = 2 - (x/2)
y - 8 = -x/2
or
x + 2y - 16 = 0
----------------------------
b).
L2 passes through origin and has slope of -4
y = -4x is the equation for L2
----------------------------
c).
Solve for y from L1

y = 8 - x/2

set L1 = L2

8 - x/2 = -4x
16 = -8x - x
16 = -7x
x = -16/7

Plug to either L1 or L2 to get y-coordinate

y = -4(-16/7)
y = 64/7

Answer:

C(-16/7; 64/7)
1
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