An athlete swings a 5.30 kg ball horizontally on the end of a rope. The ball moves in a circle of radius 0.800

An athlete swings a 5.30 kg ball horizontally on the end of a rope. The ball moves in a circle of radius 0.800 m at an angular speed of 0.490 rev/s.
(a) What is the tangential speed of the ball?
m/s

(b) What is its centripetal acceleration?
m/s2

(c) If the maximum tension the rope can withstand before breaking is 107 N, what is the maximum tangential speed the ball can have?
m/s



just a little help plz ill give best answer i don't seem to get it thank you soo much

tangential speed is in m/s, so just work out how many metres are in revolution (Circumference of a circle is 2 pi radius), and multiply that by 0.490

centripetal acceleration = v^2 / r (where v is tangential speed from (a) and r is 0.800m)

the maximum tension is equal to the centripetal force in this case.
centripetal force = m v^2 / r
107 = 5.30 x v^2 / 0.800 (where v is tangential speed from (a))

Hope this helps. :)