(a) How large is the frictional force? N
(b) What is the coefficient of friction?
(b) What is the coefficient of friction?
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Hello Fender
The sum of the forces on the object in the direction of movement equals the mass times the acceleration.
What is the sum of the forces in the x direction? The applied force (F) in the positive direction and the friction force (Ff) in the negative direction.
sum of forces = F - Ff = m*a
Solve for Ff
Ff = F - m*a
Ff = 38 .0 N - (5 kg * 6.3 m/s^2)
Ff = 7.5 N (in the minus x direction)
B) Ff = u * N = u * m * g
I am using (u) for coefficient of friction, but it is kinetic, not static.
u = Ff / (m*g)
u = 7.5 N / (5 kg * 9.81 m/s^2)
u = 0.15
Good Luck
The sum of the forces on the object in the direction of movement equals the mass times the acceleration.
What is the sum of the forces in the x direction? The applied force (F) in the positive direction and the friction force (Ff) in the negative direction.
sum of forces = F - Ff = m*a
Solve for Ff
Ff = F - m*a
Ff = 38 .0 N - (5 kg * 6.3 m/s^2)
Ff = 7.5 N (in the minus x direction)
B) Ff = u * N = u * m * g
I am using (u) for coefficient of friction, but it is kinetic, not static.
u = Ff / (m*g)
u = 7.5 N / (5 kg * 9.81 m/s^2)
u = 0.15
Good Luck