http://www.flickr.com/photos/51672712@N0…
Okay, after that, can I cancel the "sin" out and and then put the 2 in front of the integral?
Okay, after that, can I cancel the "sin" out and and then put the 2 in front of the integral?
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hi, what you should do instead of your last step is:
since you know du/dx = 2sinx
you know du = 2sinx dx
your last sentence should be:
integrate(0.5 u^3 du)
0.5 because you need to have a 2sinx dx to replace with du and since you dun have a 2, you need to times 2 and times 0.5
since you know du/dx = 2sinx
you know du = 2sinx dx
your last sentence should be:
integrate(0.5 u^3 du)
0.5 because you need to have a 2sinx dx to replace with du and since you dun have a 2, you need to times 2 and times 0.5
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∫[(sin(x)][1-2cos(x)]³dx u=1-2cos(x) du=2sin(x)dx
∫(u³)(du/2=(1/8)u^4+c
=(1/8)[1-2cos(x)]^4 +c
∫(u³)(du/2=(1/8)u^4+c
=(1/8)[1-2cos(x)]^4 +c
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I guess