A mn wandering in the desert walks 2.6 miles in the direction S 36* W. he then turns 90* and walks 3.2 miles in the direction N 54* W. At that time, how far is he from his starting point, and what is his bearing from his starting point?
Im extremely lost here, can anyone help me out with this?
Im extremely lost here, can anyone help me out with this?
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E----W and N-----S are in fact the XOY axis..
he is moving in the shape of a right triangle with the sides of 2.6 and 3.2
the distance from starting point will be the hypotenuse length:
D^2 = 2.6^2 + 3.2^2 = 17
D = 4.123 miles
the bearing from the starting point:
arsin X = arcsin (3.2/4.123 ) = 50.9 degrees (X is the angle opposite to the side 3.2)
the initial angle he walked was 36* with the NS axis,
the bearing will be 90 - (36+ 50.9) = 3.1 degrees
he is moving in the shape of a right triangle with the sides of 2.6 and 3.2
the distance from starting point will be the hypotenuse length:
D^2 = 2.6^2 + 3.2^2 = 17
D = 4.123 miles
the bearing from the starting point:
arsin X = arcsin (3.2/4.123 ) = 50.9 degrees (X is the angle opposite to the side 3.2)
the initial angle he walked was 36* with the NS axis,
the bearing will be 90 - (36+ 50.9) = 3.1 degrees