Trigonometry -A man walking in the desert walks 2.6 miles in the direction S 36* W
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Trigonometry -A man walking in the desert walks 2.6 miles in the direction S 36* W

[From: ] [author: ] [Date: 11-10-13] [Hit: ]
9 degrees (X is the angle opposite to the side 3.the initial angle he walked was 36* with the NS axis,the bearing will be 90 - (36+ 50.9) = 3.......
A mn wandering in the desert walks 2.6 miles in the direction S 36* W. he then turns 90* and walks 3.2 miles in the direction N 54* W. At that time, how far is he from his starting point, and what is his bearing from his starting point?

Im extremely lost here, can anyone help me out with this?

-
E----W and N-----S are in fact the XOY axis..

he is moving in the shape of a right triangle with the sides of 2.6 and 3.2

the distance from starting point will be the hypotenuse length:

D^2 = 2.6^2 + 3.2^2 = 17

D = 4.123 miles

the bearing from the starting point:

arsin X = arcsin (3.2/4.123 ) = 50.9 degrees (X is the angle opposite to the side 3.2)

the initial angle he walked was 36* with the NS axis,

the bearing will be 90 - (36+ 50.9) = 3.1 degrees
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