Work-Kinetic Energy physics question please help!!
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Work-Kinetic Energy physics question please help!!

[From: ] [author: ] [Date: 11-10-13] [Hit: ]
What is the change in the kinetic energy of the car?Please help me this is due tomorrow and I have no idea how to do it.Please help me with step by step.Thank you-K.E.86 km/hr = 86*1000m/60^2 to give: 23.......
With brakes fully applied, a 1390 kg car decelerates from a speed of 86.0 km/hr. What is the work done by the braking force in bringing the car to a stop?
What is the change in the kinetic energy of the car?


Please help me this is due tomorrow and I have no idea how to do it. Please help me with step by step. Thank you

-
K.E. = 1/2mv^2
We need the right units so:
86 km/hr = 86*1000m/60^2 to give: 23.8m/sec

so kinetic energy of the car is:

.5(1390)(23.8)^2 = 396,622J

This is both the change in kinetic energy and the work done to stop the car.
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