With brakes fully applied, a 1390 kg car decelerates from a speed of 86.0 km/hr. What is the work done by the braking force in bringing the car to a stop?
What is the change in the kinetic energy of the car?
Please help me this is due tomorrow and I have no idea how to do it. Please help me with step by step. Thank you
What is the change in the kinetic energy of the car?
Please help me this is due tomorrow and I have no idea how to do it. Please help me with step by step. Thank you
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K.E. = 1/2mv^2
We need the right units so:
86 km/hr = 86*1000m/60^2 to give: 23.8m/sec
so kinetic energy of the car is:
.5(1390)(23.8)^2 = 396,622J
This is both the change in kinetic energy and the work done to stop the car.
We need the right units so:
86 km/hr = 86*1000m/60^2 to give: 23.8m/sec
so kinetic energy of the car is:
.5(1390)(23.8)^2 = 396,622J
This is both the change in kinetic energy and the work done to stop the car.