Consider an airplane that normally has an airspeed of 100-km/h in a 100-km/h crosswind blowing from west to east. Calculate its ground velocity when its nose is pointed north in the crosswind.
Having trouble figuring this one out, any help is appreciated.
Having trouble figuring this one out, any help is appreciated.
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Hello
the speed over ground is √(100^2 + 100^2) = 100*√(2) km/h (Pythagoras)
(But the airplane flies actually to north east in this case (track is north east), although it is heading north (drift angle = 45°)
Hope this is what you mean.
If it would try to actually fly course north (track = north) , it would not have a chance, because its own velocity and wind velocity are equal.)
Regards
the speed over ground is √(100^2 + 100^2) = 100*√(2) km/h (Pythagoras)
(But the airplane flies actually to north east in this case (track is north east), although it is heading north (drift angle = 45°)
Hope this is what you mean.
If it would try to actually fly course north (track = north) , it would not have a chance, because its own velocity and wind velocity are equal.)
Regards