Q: A person walks first at a constant speed of 5.00 m/s along a straight line from point A to point B and then back along the same like from point B to point A at a constant speed of 3.00 m/s. What is her average speed over her entire trip?
I need help setting up this problem. I understand that average speed is total distance traveled divided by time elapsed.
I need help setting up this problem. I understand that average speed is total distance traveled divided by time elapsed.
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Assume the distance from A to B is d. You walk 5 m/s for a duration d/5 and 3 m/s for a duration d/3. Your average speed is distance/time = 2d / (d/5 + d/3) = 2/(1/5+1/3) = 2/(8/15) = 30/8 = 3.75 m/s.
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use strong cable ur broblem will be solve easy.
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4 m/s