Average speed problem
Favorites|Homepage
Subscriptions | sitemap
HOME > Physics > Average speed problem

Average speed problem

[From: ] [author: ] [Date: 11-10-10] [Hit: ]
You walk 5 m/s for a duration d/5 and 3 m/s for a duration d/3. Your average speed is distance/time = 2d / (d/5 + d/3) = 2/(1/5+1/3) = 2/(8/15) = 30/8 = 3.75 m/s.-use strong cable ur broblem will be solve easy.......
Q: A person walks first at a constant speed of 5.00 m/s along a straight line from point A to point B and then back along the same like from point B to point A at a constant speed of 3.00 m/s. What is her average speed over her entire trip?

I need help setting up this problem. I understand that average speed is total distance traveled divided by time elapsed.

-
Assume the distance from A to B is d. You walk 5 m/s for a duration d/5 and 3 m/s for a duration d/3. Your average speed is distance/time = 2d / (d/5 + d/3) = 2/(1/5+1/3) = 2/(8/15) = 30/8 = 3.75 m/s.

-
use strong cable ur broblem will be solve easy.

-
4 m/s
1
keywords: problem,Average,speed,Average speed problem
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .