Use the Pythagorean Theorem to find the distance to the nearest tenth, between F(9, 5) and G(-2, 2). (Hint: Place F and G on the coordinate plane. Then sketch a triangle with FG as the hypotenuse.)
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Make one side of your right triangle down the x axis: 9 --2 =11, and the second side of your right triangle down the y axis: 5-2 = 3. The hypotenuse, FG, will be the distance between the points. We can use Pythagoras to find that. 11^2 = 121, 3^2 = 9. FG = sqrt(121 + 9) = sqrt(130), which is about 11.4
QED
QED
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Pythagorean Theorem states A(cubed)xB(cubed)=C(cubed)
So place point F and G on a coordinate plane
Wait wait wait.... this doesn't make sense!!
Not enough information, WHERE IS THE THIRD POINT. you need the right angle point.
So the Pythagorean thero is reversed. Work backwards. 3(cubed)x11(cubed)=130 take sqr.root
The answer is 11.4017....
So place point F and G on a coordinate plane
Wait wait wait.... this doesn't make sense!!
Not enough information, WHERE IS THE THIRD POINT. you need the right angle point.
So the Pythagorean thero is reversed. Work backwards. 3(cubed)x11(cubed)=130 take sqr.root
The answer is 11.4017....
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potato