AP Physics, short time, I need a hero. Please

It's not much, but I don't know crap. Please, can someone answer and explain the question?

-- A motorist drives north for 35.0 minutes at 85.0 km/h and then stops for 15.0 minutes. He then continues north, traveling 130 km in 2.00 h. (a) What is his total displacement? (b) What is his average velocity?

a) the 1st distance(displacement) he will travel is =v*t=(85/60)*35=49.58 Km..
and 2nd distance(displacement) =130 km
so the total disp. becomes =130+49.58=179.58=180 km

b) then the avg velocity is given by
Vav= total disp. / total time taken
= 180/ (35+15+120) [2 hrs = 120 minutes...so total time becomes 35+15+120 ]
=1.06 km/ min
=63.5 km/hr

a) Displacement is the total distance traveled from the starting point. 35.0 minutes is equal to 35.0/60 = .583 hours. In the first leg of the trip, the motorist went (.583 hours)(85.0 km/hour) = 49.6 km. In the second leg of the trip he just sits there for 15 minutes, so he goes 0 km. Finally, he travels 130 km. So, the total displacement is 49.6 km + 0 km + 130 km = 179.6 km.

b) Average velocity is given by the total displacement over the time taken. We know the displacement, so now we must find the total time taken on the trip: 35.0 minutes + 15.0 minutes + 120 minutes = 170 minutes. 179.6 km / 170 minutes = 1.06 km/minute

Total displacement=0.63333*85+130=179.583 km
35 min=35/60= .63 hours
Average velocity= 179.583/(.6333+.25+2)=63.38 km/h

85 plus 130

b. 85 plus 130 / 35 plus 15 plus 120 minues convert to km / h