An open organ pipe is 0.66 long....

a) If the speed of sound is 340 m/s , what is the pipe's fundamental frequency?

b) What are the frequencies of the first two overtones?

a) fn = (n+1) *v/2L
--> the first harmonic(fundamental frequency)--> n = 0
fo =( 0+1)*340/0.66 = 257.58 Hz

b) f2 = (2+1) * 340/(2*0.66) = 772.73 Hz