h = -30cos Θ+ 35
What is the max and min? I don't know how to find it..
What is the max and min? I don't know how to find it..
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Ok, the range before adding 35 is from -30 to 30. Add the 35 to each. Your max is 30+35 = 65, and your min is -30+35 = 5.
Jen
Jen
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Since cos has a max of 1 and a min of -1, the first term will at a minimum subtract 30 from the 35, and will at a maximum add 30 to the 35. Thus,
min = 35 - 30 = 5
max = 35 + 30 = 65
min = 35 - 30 = 5
max = 35 + 30 = 65
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just study it like any other function. find the derivative h'= 30sin Θ
h'= 0 if Θ1= (2k+1)π or Θ2= 2k π where k is a natural number
h(Θ1)= 65 which would be the max
h(Θ2)= 5 which would be the min
h'= 0 if Θ1= (2k+1)π or Θ2= 2k π where k is a natural number
h(Θ1)= 65 which would be the max
h(Θ2)= 5 which would be the min
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You don't know -1 < cos Θ <1 for every Θ?
Use this to get 5 < h < 65.
Use this to get 5 < h < 65.