Factor completely 27a^3+b^3
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This is the "sum of cubes" factorization:
x^3 + y^3 = (x+y)(x^2 - xy + y^2)
In this case, x = 3a and y = b, so the answer is:
(3a + b)(9a^2 - 3ab + b^2)
x^3 + y^3 = (x+y)(x^2 - xy + y^2)
In this case, x = 3a and y = b, so the answer is:
(3a + b)(9a^2 - 3ab + b^2)
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There is no common factor between 27a^3 and b^3 except for 1.
Therefore you just leave it as 27a^3 + b^3.
Therefore you just leave it as 27a^3 + b^3.
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27a^3+b^3 in factored version is: (3a+b)(9a^2-3ab+b^2)