A water tank is in the form of a right circular cylinder with height 20 ft and radius 6 ft. If the tank is half full of water, find the work required to pump all of the water over the rim.( water weighs 62.5 lb/ft^3)
Use calculus! Pleaseeeeeeeeeee some one help me!!!
Use calculus! Pleaseeeeeeeeeee some one help me!!!
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You don't need calculus
Volume of a right circular cylinder = pi(r^2)h
So the volume in this situation is half of the height or ten feet tall
Volume= 36(pi)(10)
Volume= 1130 ft^3 or 344.55 m^3
work=mass(distance)(gravity)
mass of water is 1000 KG/m^3
and since we need to fill up the tank's volume of 344.55 m^3
we have
work=344.55(1000)(9.8(gravity constant))
which means
work=3376550 joules or 3376.55 Kj
Volume of a right circular cylinder = pi(r^2)h
So the volume in this situation is half of the height or ten feet tall
Volume= 36(pi)(10)
Volume= 1130 ft^3 or 344.55 m^3
work=mass(distance)(gravity)
mass of water is 1000 KG/m^3
and since we need to fill up the tank's volume of 344.55 m^3
we have
work=344.55(1000)(9.8(gravity constant))
which means
work=3376550 joules or 3376.55 Kj