What will the volume of a 0.50 M solution be if it contains 25 grams of calcium hydroxide?
So, I started out doing the problem by using the molarity equation. i converted the 25grams to moles and then divided it by the .50 assuming that would give me the volume. I got .754, but the answer is 680ml. what did i do wrong?
So, I started out doing the problem by using the molarity equation. i converted the 25grams to moles and then divided it by the .50 assuming that would give me the volume. I got .754, but the answer is 680ml. what did i do wrong?
-
Ca(OH)2 = 74.093 g/mol
25g / 74.093 g/mol = 0.3374 mol Ca(OH)2
0.3374 mol / 0.5 mol/L = 0.6748 L Ca(OH)2
which is equal to approximately 675 mL, or 680 rounded up.
25g / 74.093 g/mol = 0.3374 mol Ca(OH)2
0.3374 mol / 0.5 mol/L = 0.6748 L Ca(OH)2
which is equal to approximately 675 mL, or 680 rounded up.
-
if you got the moles then divided by .5 the answer should be .674 which is in liters the multiply it by 1000 to get the answer which is approx. 680ml ok?