1. Please factor completely: 10xy + 3y + 20ax + 6a

& 2. factor completely: 3ab(x + 1) − 2(x + 1)

thank you so much! i appreciate your help a lot! ♥

Steps:

1. Factor like terms
2. Group the common factors and collect the remaining terms.

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1. 10xy + 3y + 20ax + 6a
= y(10x + 3) + 2a(10x + 3)
= (y + 2a)(10x + 3)

2. Group x + 1 and collect the terms.

(3ab - 2)(x + 1)

I hope this helps!

10xy + 3y + 20ax + 6a

y*(10*x + 3) + 2*a*(10*x + 3)

10*x + 3 is common to both terms....

(y + 2*a)*(10*x + 3)

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3ab(x + 1) − 2(x + 1)

(x + 1) is common to both terms

(x + 1)*(3*a*b - 2)

y(10x + 3) + 2a(10x + 3)
(y + 2a)(10x + 3)

(3ab - 2)(x + 1)

Y(10x+3)+2a(10x+3)=(10x+3)(y+2a)