Physics,maximum range? help!

An astronaut on the Moon fires a projectile from a launcher on a level surface so as to get the maximum range.
If the launcher gives the projectile a muzzle velocity of 23m/s , what is the range of the projectile? [Hint: The acceleration due to gravity on the Moon is only onesixth of that on the Earth.]

help me i dnt kno how to beging, step by step plz

Maximum range is attained when the angle of projection is 45 degree.
R = u^2/g = 23^2*6/9.8 = 324 m



======================================…
Range = Ucosθ * time of flight.

Time of flight = 2 u sinθ / g ( Note the time to go up is u sinθ / g)

R = 23 * cos 45 * 2* 23 sin45 / ( 9.8/6) = 324 m
====================================

Since it did not give you an angle, I beileve you have to use the maximum range equation.
Rmax = (Vo^2)/g
You know your Initial velocity = 23 m/s and your gravity, g. is equal to (g/6)

Rmax = (Vo^2)/g
Rmax = (23^2)/(9.81/6)
Rmax = 323.55 meters

Launch angle required = 45 degrees.
Moon g figure = (9.8/6) = 1.63m/sec^2.
Time in flight = 2 ((sin L x Vi)/1.63), = 19.955 secs.
Horizontal velocity comonent = (cos 45) x 23, = 16.2633m/sec.
(16.2633 x 19.955) = 325.2 metres range.

R = (v^2sin2A)/g

R = range = ?
v = initial velocity = 23 m/s
A = angle of velocity = 45 degrees (angle for maximum range)
g = gravity = 1.63 m/s^2

R = (23^2 * sin90) / 1.63
= 324.54 metres

it will be in pluto within the next 2 seconds