Hi I need some help simplifying these trigonomic expressions:
1) sinx/tanxcosx
I tried solving this one, i ended up with:
sinx/(sinx/cosx)(cosx)
= sinx (not sure if thats right)
2) cscθtanθsecθ
This is what I've solved so far:
= 1/sinθ x sinθ/cosθ x 1/cosθ
not sure what to do next??
Thanks for trying :)
1) sinx/tanxcosx
I tried solving this one, i ended up with:
sinx/(sinx/cosx)(cosx)
= sinx (not sure if thats right)
2) cscθtanθsecθ
This is what I've solved so far:
= 1/sinθ x sinθ/cosθ x 1/cosθ
not sure what to do next??
Thanks for trying :)
-
1) sinx/[tanxcosx]
= sinx/ [ sin x/cos x * cosx]
= sin x/ sin x
= 1
answer
2) cscθtanθsecθ
= 1/sinθ * sinθ / cos θ * 1 /cos θ
= 1 / cos ^2 θ
answer
= sinx/ [ sin x/cos x * cosx]
= sin x/ sin x
= 1
answer
2) cscθtanθsecθ
= 1/sinθ * sinθ / cos θ * 1 /cos θ
= 1 / cos ^2 θ
answer