MATH HELP 10 POINTS TO BEST

solve -41 ≤ 9x+ 13 ≤ 53 and graph the solution on a number line

sorry i dont have a graph to show u guys but it says
Use the graph below of y=|x-2| to solve the inequality 3 < |x-2|

for -41≤9x+13≤53 -6≤x≤40/9
The number line looks a bit like this:
←|---•---|---|---|---|---|---|
‹ -7 -6 -5 -4 -3 -2 -1 ‹0
---|---|---|---|--•|→
‹‹1‹‹‹2‹‹3‹‹4‹|5
‹‹‹‹‹‹‹‹‹‹‹‹‹‹‹40/9
all points between the two points are answers (sorry about the line skip, most of the number line wouldn't show on the post and I used ‹ because it was the only way to to evenly space everything)
here are the steps:
1) -41≤9x+13≤53
2) -54≤9x≤40
3) -6≤x≤40/9

for 3<|x-2| x<-1 or x>5 (in the graph, i bet there is a shaded area, and all you have to do is find the areas where y>3 since y=|x-2|, which makes the question asking where is y>3)
if there wasn't a graph, you would have to do this:
1) 3<|x-2|
2) 3x-2
3) 3+2x-2+2
4) 5x
5) x>5‹‹‹‹‹‹‹‹‹‹‹‹‹‹‹‹‹x<-1
since x cannot be greater than 5 and less than -1 at the same time so the answer comes out to be x>5 or x<-1

for the top, all you do is split it into 2 inequalities, -41<= 9x+13 and 9x+13<= 53 and solve for x. to graph it, use a number line and use 2 pts and shade the line to the left or right of the pts (depending on the sign of the inequality). if the lines converge in the middle, shade only in the middle, not past the pts
also, post a pic of the grap on flickr or something and add a link to it so other ppl can help you with the other problem