Calculus question : d/dx[sin(nx)] where, n= constant

[From: ] [author: ] [Date: 11-10-07] [Hit: ]

d/dx[sin(nx)]

= d/dx[sin(nx)]*d/dx(nx)

= cos(nx)*n

=n*cos(nx)

y = sin(nx)
Let z = nx
dz/dx = n
y = sinz
dy/dz = cosz
dy/dx = dy/dz*dz/dx
= ncosz
=ncos(nx)

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