Please answer these with solution...for my projects sake
1. A painting measuring 6 dm by 8 dm has a frame of uniform width with a total area of the painting. How wide is the frame? Round with the nearest hundred.
2. A man can row 8 km downstream and back in 6 hours. If the rate of the stream is 1 km per hour, what is the rate of the man rowing in still water?
3. A group of students equally shouldered the price of a broken laboratory instrument which is 60 pesos. If there had been three more students in their group, the cost of each share would have been 1 peso less. How many students were in the group?
1. A painting measuring 6 dm by 8 dm has a frame of uniform width with a total area of the painting. How wide is the frame? Round with the nearest hundred.
2. A man can row 8 km downstream and back in 6 hours. If the rate of the stream is 1 km per hour, what is the rate of the man rowing in still water?
3. A group of students equally shouldered the price of a broken laboratory instrument which is 60 pesos. If there had been three more students in their group, the cost of each share would have been 1 peso less. How many students were in the group?
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Answer 1: Insufficient data
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8/(x + 1) + 8/(x - 1) = 6
8x - 8 + 8x + 8 = 6(x² - 1)
16x = 6x² - 6
6x² - 16x = 6
x² - 4/3x = 1 + (- 4/3)²
x² - 4/3x = (9 + 16)/9
(x - 4/3)² = 25/9
x - 4/3 = 5/3
x = 9/3 or 3
Answer 2: 3 km/hr
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60/x - 60/(x + 3) = 1
60x + 180 - 60x = x² + 3x
x² + 3/2x = 180 + (3/2)²
x² + 3/2x = (720 + 9)/4
(x + 3/2)² = 729/4
x + 3/2 = 27/2
x = (27 - 3)/2
x = 24/2 or 12
Answer 3: 12 students
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8/(x + 1) + 8/(x - 1) = 6
8x - 8 + 8x + 8 = 6(x² - 1)
16x = 6x² - 6
6x² - 16x = 6
x² - 4/3x = 1 + (- 4/3)²
x² - 4/3x = (9 + 16)/9
(x - 4/3)² = 25/9
x - 4/3 = 5/3
x = 9/3 or 3
Answer 2: 3 km/hr
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60/x - 60/(x + 3) = 1
60x + 180 - 60x = x² + 3x
x² + 3/2x = 180 + (3/2)²
x² + 3/2x = (720 + 9)/4
(x + 3/2)² = 729/4
x + 3/2 = 27/2
x = (27 - 3)/2
x = 24/2 or 12
Answer 3: 12 students