Linear algebra transpose. someone rescue me

If (2A−I)T=[ 5...-6] (all one matrix)
................[.0.....1]

then A = ?
iknow that to get rid of the t we must transpose again
what else do i do to get A?

thank you for your help :) i appreciate it

It's been a while, but here goes:

(2A − I)T = [5...-6]
.................[0....1]

Transpose again (because the transposed transposed matrix is the original):

(2A − I) = [ 5...0]
...............[-6...1]

Add the identity matrix (2x2 of course):

(2A) = [ 6...0]
..........[-6...2]

Divide by 2:

(A) = [ 3...0]
.........[-3...1]

please!

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The identity matrix was subtracted (that's what 2A-I meant). To cancel, we must add the identity matrix of the same size, 2x2. This is a matrix with 1's as the diagonals and 0's everywhere else. Adding this like regular matrix addition, 5 became 6, 1 became 2, and the non-diagonals didn't change.

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