It's a very basic exercise to create a lewis structure, but I am confused as to how to get the correct amount of electron needed. My molecule is NaHCO3, since it's ionic I picked out HCO3 (-1)...
then I get the electrons Needed which are 2(H) + 8 x 4 (C and 3 O) = 34
Then the electrons Available: 1(H) + 4(C) + 3x6 (O) + 1 = 24
Finally Shared electrons: 34 - 24 = 10 (covalent bonds: 10/2 = 5)
But I am still confused with this example, why 2 Hydrogens and 8 x 4 Carbon and Oxygen... I know there are 3 oxygen but what about the other 2?
(I'm a high school student, a simple answer would be great xD)
then I get the electrons Needed which are 2(H) + 8 x 4 (C and 3 O) = 34
Then the electrons Available: 1(H) + 4(C) + 3x6 (O) + 1 = 24
Finally Shared electrons: 34 - 24 = 10 (covalent bonds: 10/2 = 5)
But I am still confused with this example, why 2 Hydrogens and 8 x 4 Carbon and Oxygen... I know there are 3 oxygen but what about the other 2?
(I'm a high school student, a simple answer would be great xD)
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It is both Ionic and covalent
take out the Na+ put it to the side
Draw HCO3-
Here is carbonate, just add an H
http://www.kentchemistry.com/links/bondi…
take out the Na+ put it to the side
Draw HCO3-
Here is carbonate, just add an H
http://www.kentchemistry.com/links/bondi…