Write the corresponding mRNA sequence encoded for by this segment of DNA

3’ TACATATGATTAACT 5’


Use the genetic code table on http://www.nature.com/scitable/nated/content/42614/pierce_15_10_MID_1.jpg to determine the amino acids encoded for by the mRNA sequence. Once a stop codon appears, write STOP and don’t add more amino acids. Write the three letter codes for each of the amino acids (e.g. Met) in the peptide chain. (Write this under the mRNA so that each codon lines up with the amino acid it encodes).

d. (0.5 point) Of the following mutations, which one would produce a product with the same amino acid makeup as the original? (no change to the amino acids in the chain)

3’ TACATTTGATTAACT 5’

3’ TACATATGCTTAACT 5’

3’ TACATATGATTTACT 5’

3’ TACATATGATTAACC 5’

Luckily, the directionality of the DNA strand is correct; that is, we always need to transcribe the DNA strand that runs 3' to 5'.


DNA: 3’ TACATATGATTAACT 5’
RNA: 5' AUGUAUACUAAUUGA 3'

Now we break the RNA (mRNA) into triplets (codons) and "translate".
RNA: 5' AUG UAU ACU AAU UGA 3'
.............Met...Tyr...Thr...Asn...ST…

PS: That last one is STOP, but because of the many periods to try to line things up, the site messes it up.



This sequence (the second of the four options) will produce the same amino acids.
3’ TACATATGCTTAACT 5’

A pairs with T (U), C pairs with G so on and so forth it will be read 5' to 3' if the first chain is 3' to 5'. stop codons vary there is about 3 or 4 i think, maybe (probably) more. AUG is the only one i remember off the top of my head