Can someone help me with this physics problem!
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Can someone help me with this physics problem!

[From: ] [author: ] [Date: 11-11-02] [Hit: ]
M and a 2kg mass m are suspended vertically from the top of a massless, frictionless pulley using massless rope. Assume the system is initially at rest and at t=0 mass, M is released (in the diagram they are both hanging straight down with mass, m hanging lower than mass, M).......
An 8.0 kg mass, M and a 2kg mass m are suspended vertically from the top of a massless, frictionless pulley using massless rope. Assume the system is initially at rest and at t=0 mass, M is released (in the diagram they are both hanging straight down with mass, m hanging lower than mass, M).

a) use Newton's second law of the motion of mass to write an equation for M.
I got F = 8a, is that right?
b) Repeat part a for the motion of mass m
I got F = 2a
c) Solve for the magnitude of the acceleration of each block.
I have no idea how to do this!! I was trying to cancel out the Fnet.. but I think I over thought it..I don't know.
d) If M drops 1.5m how much work is done by gravity on the two block system.

Can someone help me???

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You forgot about gravity.
I can't do this in my head quickly, but basically there is a downwards force 8*g on M and a downwards force 2*g on m, then an upwards forcein the rope which must be the same for both, and an acceleration of both that must be equal and opposite
So I think it's F = 8(g-a) = 2 (g+a)
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