If a mass m is attached to a given spring, its period of oscillation is T.
If two such springs are connected end to end and the same mass m is attached, is the resulting period of oscillation greater than, less than, or equal to T?
Choose the bestexplanation from among the following:
A) The longer spring stretches more easily, and hence takes longer to complete an oscillation.
B) The period of oscillation does not depend on the length of a spring, only on its force constant and the mass attached to it.
C) Connecting two springs together makes the spring stiffer, which means that less time is required for an oscillation.
thanks
If two such springs are connected end to end and the same mass m is attached, is the resulting period of oscillation greater than, less than, or equal to T?
Choose the bestexplanation from among the following:
A) The longer spring stretches more easily, and hence takes longer to complete an oscillation.
B) The period of oscillation does not depend on the length of a spring, only on its force constant and the mass attached to it.
C) Connecting two springs together makes the spring stiffer, which means that less time is required for an oscillation.
thanks
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According to Hook's law, if two springs, with same constant k, connected end to end constant will be k/2. Period is square root of m/k so it takes longer to complete an oscillation. To sum up A :)
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B) The period of oscillation does not depend on the length of a spring, only on its force constant and the mass attached to it
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asds