Physics help! A mass m=10kg is pulled by a constant force F=30N acting upward at 30 degrees..

From the horizontal. The Coefficient of sliding friction between the block and the surface is u=0.2.
a)Determine the force of friction acting on the block
b) Find the horizontal acceleration of the block

the force of friction is u N where u is the coefficient of friction and N is the normal force

we find the normal force from vertical equilibrium:

in the y direction, we have

Normal force - mg +Fsin 30=0

N = mg - F sin 30 = 10kg x 9.8m/s/s - 30N sin 30 = 83N

therefore the frictional force = 0.2*83N = 16.6N

we find the horizontal acceleration from

sum of forces in horizontal direction = m a

F cos 30 - u N = m a
26N - 16.6N = 10 a

a = 0.94m/s/s
30 cos 30