Can anyone please help with this distance/momentum problem

A 0.150 kg baseball moving at 18 m/s is slowed to a stop by a catcher in 0.009 s.

(a) What constant force did the catcher exert on the ball during this time?
300N
(b) How far did the ball travel before stopping?
m

for 1. Impulse = change in momentum
F t = m v
so F = m v / t
= 0.15 * 18 / 0.009 (= 300N)

for the second part there are many different ways.
The average speed is 1/2 the initial speed. ( i.e 9 m/s)
so distance = speed * time = 9 * 0.009
= 0.081 m

Or you could have used energy = force * distance

Or V = at from which you find a
then s = 1/2 a t^2

All are quite valid and give the same answer.