On combustion 0.5 Mole of the saturated hydrocarbon used 123.2 liters of oxygen. Please find the formula for the connection.
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If we take the volume of the O2 as being at STP:
1mol gas at STP = 22.4L
123.2L = 123.2/22.4 = 5.5 mol O2
0.5mol HC reacts with 5.5mol O2
1mol HC reacts with 11mol O2
C7H16 + 11 O2 = 7 CO2 + 8 H2O
The hydrocarbon is C7H16 = heptane
1mol gas at STP = 22.4L
123.2L = 123.2/22.4 = 5.5 mol O2
0.5mol HC reacts with 5.5mol O2
1mol HC reacts with 11mol O2
C7H16 + 11 O2 = 7 CO2 + 8 H2O
The hydrocarbon is C7H16 = heptane