x^2 + 12x + 32= 0 :)
thank you
thank you
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x^2 + 12x + 32 = 0
We need factors of 32 that add to 12, let's list the factoring pairs of 32:
(1, 32) (2, 16) (4, 8)
Since 4 + 8 = 12, we can use this to factor the equation and get:
(x + 8) * (x + 4) = 0
We need factors of 32 that add to 12, let's list the factoring pairs of 32:
(1, 32) (2, 16) (4, 8)
Since 4 + 8 = 12, we can use this to factor the equation and get:
(x + 8) * (x + 4) = 0
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The method I use is to find two numbers that add to equal 12 and multiply to equal 32.
In this case that would be 4 and 8. Thus the factored version of this equation is (x+4)(x+8).
In this case that would be 4 and 8. Thus the factored version of this equation is (x+4)(x+8).
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Factor the equation to get
(x + 8) (x + 4) = 0
Now set the factor to 0 and solve.
x = - 8 and x = -4
(x + 8) (x + 4) = 0
Now set the factor to 0 and solve.
x = - 8 and x = -4
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x^2 + 12x + 32= 0
x^2 + 2*6*x + 6^2 -4= 0
(x+6)^2 - 2^2 = 0
(x+6+2)(x+6-2) = 0
(x+8)(x+4) = 0
Roots
x = - 8
x = - 4
x^2 + 2*6*x + 6^2 -4= 0
(x+6)^2 - 2^2 = 0
(x+6+2)(x+6-2) = 0
(x+8)(x+4) = 0
Roots
x = - 8
x = - 4
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x^2 + 8x + 4x + 32 = 0
x(x+8) + 4(x+8) = 0
(x+8) (x+4) = 0
x(x+8) + 4(x+8) = 0
(x+8) (x+4) = 0