lim as x approaches 0+ of ln(x) / cot(x)
I know you have to use L' Hospitals rule but I'm still confused :(
I know you have to use L' Hospitals rule but I'm still confused :(
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You have to use lhopital twice.
Using it the first time will give you
(1/x) / (-1/(sinx)^2) = -(sinx)^2/x
This gives you 0/0
Take the derivatives again and you get -2sinxcosx
ln(x) doesnt exist to the left of 0 so you know that the limit just approaches 0 from the right.
Using it the first time will give you
(1/x) / (-1/(sinx)^2) = -(sinx)^2/x
This gives you 0/0
Take the derivatives again and you get -2sinxcosx
ln(x) doesnt exist to the left of 0 so you know that the limit just approaches 0 from the right.