F(2) = 5 and F(3) = -1
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ax + c = y
2a + c = 5 so c = 5 - 2a
3a + c = -1 so c = -1 - 3a
5 - 2a = -1 - 3a
5 + a = -1
a = -6, c = 17
F(x) = -6x + 17 is the correct answer, not -7 as Steven said.
2a + c = 5 so c = 5 - 2a
3a + c = -1 so c = -1 - 3a
5 - 2a = -1 - 3a
5 + a = -1
a = -6, c = 17
F(x) = -6x + 17 is the correct answer, not -7 as Steven said.
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F(2) = 5 and F(3) = -1
gives you two points
(2,5) and (3,-1)
first, the slope
(y1-y2)/(x1-x2)
either point can be 1 or 2
(-1-5)/(3-2)
-6/1
-6
so you start with
y= -6x
now subtract the values of a point from their relative x and y variable
(y-5)= -6(x+2)
y-5= -6x-12
y= -6x-7
gives you two points
(2,5) and (3,-1)
first, the slope
(y1-y2)/(x1-x2)
either point can be 1 or 2
(-1-5)/(3-2)
-6/1
-6
so you start with
y= -6x
now subtract the values of a point from their relative x and y variable
(y-5)= -6(x+2)
y-5= -6x-12
y= -6x-7