Rearrange eqation to solve for initial velocity (V0) .
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Rearrange eqation to solve for initial velocity (V0) .

[From: ] [author: ] [Date: 11-11-01] [Hit: ]
taking SQRT of both sides V0 = x * SQRT( g / (2*y) ),It could also be stated as,Which is the same thing.The SQRT( 2*y/g ) is in units of time.......
y= 1/2 g (x/V0)^2

how can this be rearranged to solve for V0?
note: ^2 is "to the power of 2"

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Well, something like this?

    y = (1/2) * g * (x/V0)^2, initial statement
    2 * y / g = x^2 / V0^2, multiply both sides by (2/g)
    V0^2 = x^2 / (2 * y / g), exchange across = sign
    V0 = SQRT( x^2 / (2*y/g) ), taking SQRT of both sides
    V0 = x * SQRT( g / (2*y) ), pulling x out and inverting fraction

It could also be stated as,

    V0 = x / SQRT( 2*y/g )

Which is the same thing. The SQRT( 2*y/g ) is in units of time.
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