A simple pendulum of length 2.6 m makes 9.0 complete swings in 28.8 s.
What is the acceleration of gravity at the location of the pendulum?
g=_____m/s^2
thanks
What is the acceleration of gravity at the location of the pendulum?
g=_____m/s^2
thanks
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The period is 28.8 / 9 = 3.2 seconds
Pendulum period in seconds
T ≈ 2π√(L/g)
or, rearranging:
g ≈ 4π²L/T²
L ≈ T²g/4π²
L is length of pendulum in meters
g is gravitational acceleration = 9.8 m/s²
g ≈ 4π²L/T² = 4π²(2.6)/(3.2)² = 10.024 m/s²
which is an impossibly high value for here on earth.
Pendulum period in seconds
T ≈ 2π√(L/g)
or, rearranging:
g ≈ 4π²L/T²
L ≈ T²g/4π²
L is length of pendulum in meters
g is gravitational acceleration = 9.8 m/s²
g ≈ 4π²L/T² = 4π²(2.6)/(3.2)² = 10.024 m/s²
which is an impossibly high value for here on earth.