I'm so confused with this..
Can you help?
What is the normal force acting on a 8kg mass which is being pulled at a constant velocity of 7 m/sec by a rope having a tension of 45 newtons at an angle of 41 degrees to the horizontal?
What is the normal force acting on a 8kg mass which is being pushed at a constant velocity of 7 m/sec by a force of 45 newtons along a rigid handle that makes and angle of 41 degrees to the horizontal?
Can you help?
What is the normal force acting on a 8kg mass which is being pulled at a constant velocity of 7 m/sec by a rope having a tension of 45 newtons at an angle of 41 degrees to the horizontal?
What is the normal force acting on a 8kg mass which is being pushed at a constant velocity of 7 m/sec by a force of 45 newtons along a rigid handle that makes and angle of 41 degrees to the horizontal?
-
'Normal force' means the force at right angles to the surface the object is on.
The first question is not written clearly - the object could be being pulled through the air by the rope at 41 degrees - but I'll assume it's being pulled along a flat, level surface. In that case, the normal force is vertical.
The force will be made up of two components, one the weight of the mass, and the other the pull from the rope. The weight will act downward and the pull upward.
The weight is just given by F(w) = mg = 8*9.8 = 78.4 N downward.
The lifting force from the rope will be one component, given by F(y) = Fcos(theta) = 45cos41 = 34 N upward.
Since they act in opposite directions, subtract them, and the resultant normal force is 44.4 N downward.
The second question is even more confusingly written. Is the object sliding along the handle at 41 degrees, or sliding along the floor, being pushed by the handle? Maybe seek some clarification from your teacher, but the explanation above should help you work it out.
The first question is not written clearly - the object could be being pulled through the air by the rope at 41 degrees - but I'll assume it's being pulled along a flat, level surface. In that case, the normal force is vertical.
The force will be made up of two components, one the weight of the mass, and the other the pull from the rope. The weight will act downward and the pull upward.
The weight is just given by F(w) = mg = 8*9.8 = 78.4 N downward.
The lifting force from the rope will be one component, given by F(y) = Fcos(theta) = 45cos41 = 34 N upward.
Since they act in opposite directions, subtract them, and the resultant normal force is 44.4 N downward.
The second question is even more confusingly written. Is the object sliding along the handle at 41 degrees, or sliding along the floor, being pushed by the handle? Maybe seek some clarification from your teacher, but the explanation above should help you work it out.