The parachute on a race car that weighs 8780 N opens at the end of a quarter-mile run when the car is traveling 27 m/s. What net retarding force (magnitude) must be supplied by the parachute to stop the car in a distance of 880 m
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The acceleration required to bring the car from 27m/s to a stop is:
v² = v₀² + 2aΔx
a = (v² - v₀²) / 2Δx
= [0 - (27m/s)²] / 2(880m)
= -0.41m/s²
Then, the net retarding force from Newton’s 2nd law is:
F = ma
= (8780N/9.81m/s²)(-0.41m/s²)
= -370N (minus as it friction opposes motion)
Hope this helps.
v² = v₀² + 2aΔx
a = (v² - v₀²) / 2Δx
= [0 - (27m/s)²] / 2(880m)
= -0.41m/s²
Then, the net retarding force from Newton’s 2nd law is:
F = ma
= (8780N/9.81m/s²)(-0.41m/s²)
= -370N (minus as it friction opposes motion)
Hope this helps.