...artificial gravity. What must be the value of r for the astronauts to weigh 1/5 of their earth weight?
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v^2/r = accel = 9.8/5 = 2.0 m/sec^2
v = 26.5 m/s
r = v^2/2 = 702/2 = 351 m wow - that's more than I expected .... guess I'm not ready for rocket science ..
v = 26.5 m/s
r = v^2/2 = 702/2 = 351 m wow - that's more than I expected .... guess I'm not ready for rocket science ..