Let R = Earth radius = 6.37e6 m
r = distance of satellite above earth surface = 5e6 m
accel of satellite = gravitational pull or v^2/(R + r) = 9.8*[6.37e6/(5e6+6.37e6)]^2 = 3.08 m/sec^2
v = 5914 m/s answer
r = distance of satellite above earth surface = 5e6 m
accel of satellite = gravitational pull or v^2/(R + r) = 9.8*[6.37e6/(5e6+6.37e6)]^2 = 3.08 m/sec^2
v = 5914 m/s answer