a small block slides along a track fro one level to a higher level by moving through a intermediate valley. the track is frictionless until the block reaches the higher level. there a friciontial force stops the block in a distance d. assume that the block's inital speed is 10 m/s, the height difference h is 2.9m and uk(its really mu or whatever that sign is) is .32. Find the distance d that the block travels on the higher level before stopping.
I'm having a really hard time trying to conceptualize this and then figure out the math.. and help would be great!
I'm having a really hard time trying to conceptualize this and then figure out the math.. and help would be great!
-
let mass of blk = m
initial KE = 0.5 * m * 10^2
final PE gained = m * g * 2.9
work done by friction
= 0.32 * m g * d
conservation of energy
0.5 * m * 10^2 = m * g * 2.9 + 0.32 * m g * d
0.5 * 10^2 = g * 2.9 + 0.32 * g * d
d = 6.86m ---answer
initial KE = 0.5 * m * 10^2
final PE gained = m * g * 2.9
work done by friction
= 0.32 * m g * d
conservation of energy
0.5 * m * 10^2 = m * g * 2.9 + 0.32 * m g * d
0.5 * 10^2 = g * 2.9 + 0.32 * g * d
d = 6.86m ---answer